100x^2+20x-3=0

Solution for 100x^2+20x-3=0 equation:

Simplifying
100x2 + 20x + -3 = 0

Reorder the terms:
-3 + 20x + 100x2 = 0

Solving
-3 + 20x + 100x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-3 + -10x)(1 + -10x) = 0

Subproblem 1
Set the factor '(-3 + -10x)' equal to zero and attempt to solve:

Simplifying
-3 + -10x = 0

Solving
-3 + -10x = 0

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -10x = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -10x = 0 + 3
-10x = 0 + 3

Combine like terms: 0 + 3 = 3
-10x = 3

Divide each side by '-10'.
x = -0.3

Simplifying
x = -0.3
Subproblem 2
Set the factor '(1 + -10x)' equal to zero and attempt to solve:

Simplifying
1 + -10x = 0

Solving
1 + -10x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -10x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -10x = 0 + -1
-10x = 0 + -1

Combine like terms: 0 + -1 = -1
-10x = -1

Divide each side by '-10'.
x = 0.1

Simplifying
x = 0.1
Solution
x = {-0.3, 0.1}